UPSB v3
Single Member Videos / 91 Fingerpasses in 1 Minute
by Mystic
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Date: Wed, Apr 29 2009 16:54:47
This is not the best I can do. I slowed down a little near the end just to be able to hold on to the pen for a whole minute XD. Ill do a better one later. Enjoy.
Pen mod: RSVP MX
DL Link (better Quality):
http://rapidshare.com/files/227196750/91_F...s_by_Mystic.mp4 -
Date: Wed, Apr 29 2009 17:01:20
Holy crap
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Date: Wed, Apr 29 2009 18:26:24
That's.... goddam sick
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Date: Wed, Apr 29 2009 18:53:50
omg that was fast o.O
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Date: Wed, Apr 29 2009 19:10:34
that was sick.
Try 100 in a minute than you are god
xD -
Date: Wed, Apr 29 2009 23:51:58
What is this I don't even.
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Date: Thu, Apr 30 2009 00:51:04
damn, like 100 mph! nice
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Date: Thu, Apr 30 2009 00:58:21
Better than Bonkura
I was staring at the iTouch the entire time. -
Date: Thu, Apr 30 2009 01:09:36
91 fingerpasses in 60 seconds
length of opened hand= ~9 cm = 0.09 m
therefore distance per fingerpass = 0.18 m x 91 fingerpasses = 16.38 m distance (in a vertical sense of center of the pen)
v=d/t
16.38/60 = 0.273 m/s = 0.61 mph
lul
i think my calculations are fairly correct. -
Date: Thu, Apr 30 2009 15:55:30
i was staring with my mouth wide opened without noeing it...
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Date: Thu, Apr 30 2009 16:02:14
That was godly..
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Date: Thu, Apr 30 2009 19:50:58QUOTE (Stevieboy7 @ Apr 29 2009, 09:09 PM) <{POST_SNAPBACK}>91 fingerpasses in 60 seconds
length of opened hand= ~9 cm = 0.09 m
therefore distance per fingerpass = 0.18 m x 91 fingerpasses = 16.38 m distance (in a vertical sense of center of the pen)
v=d/t
16.38/60 = 0.273 m/s = 0.61 mph
lul
i think my calculations are fairly correct.
Stevieboy, are you talking bout the motion of the COP/COG going up/down the hand? Because if you measure the distance traveled by the ends of the rsvp mx, the distance would technically be greater, as the ends are moving in a circular motion when it goes up/down the hand.
In essence the mx makes 2 1/2 revolutions as it travels up/down the hand. Thus, we can calculate that the one end of the mx will travel approximately 2 x pi x 19.8cm/2 (radius of "circle" created by mx) x 2.5 (number of rotations), which is approximaetly 155.43 cm. Since this guy did 91 fingerpasses, the pen travelled 155.43cm x 91 = 14144.13 cm in total, which is around 14.1 km, which is around 8.8 miles. Since he did this in a minute, that would mean that the pen ends were travelling at 8.8 x 60 = 528 mph.
I highly doubt that you guys will understand my explanation, and i believe i made a mistake in my calculations. But the idea is that since the pen is spinning in a circle as he does fingerpasses, the distance travelled by the ends of the pen is much greater than 9 cm. If this idea is totally ludicrous and/or wrong, please excuse me. I have nothing to do right now XD
*Firewall/FlameShield* -
Date: Thu, Apr 30 2009 20:29:49QUOTE (Shimo @ Apr 30 2009, 03:50 PM) <{POST_SNAPBACK}>Stevieboy, are you talking bout the motion of the COP/COG going up/down the hand? Because if you measure the distance traveled by the ends of the rsvp mx, the distance would technically be greater, as the ends are moving in a circular motion when it goes up/down the hand.
In essence the mx makes 2 1/2 revolutions as it travels up/down the hand. Thus, we can calculate that the one end of the mx will travel approximately 2 x pi x 19.8cm/2 (radius of "circle" created by mx) x 2.5 (number of rotations), which is approximaetly 155.43 cm. Since this guy did 91 fingerpasses, the pen travelled 155.43cm x 91 = 14144.13 cm in total, which is around 14.1 km, which is around 8.8 miles. Since he did this in a minute, that would mean that the pen ends were travelling at 8.8 x 60 = 528 mph.
I highly doubt that you guys will understand my explanation, and i believe i made a mistake in my calculations. But the idea is that since the pen is spinning in a circle as he does fingerpasses, the distance travelled by the ends of the pen is much greater than 9 cm. If this idea is totally ludicrous and/or wrong, please excuse me. I have nothing to do right now XD
*Firewall/FlameShield*
14144.13 cm = 14.14413 m not KM so its significantly less, then you take stevieboy's calculation and add it on to this result for the vertical distance so
14.14 + 16.38= 30.52m
v=d/t
30.52/60= 0.51~ m/ sec, for the total speed of one of the ends (assuming all other calculations were correct), Stevies was right however as he said in a vertical sense, so his answer wasn't worried about the rotations.
and how did you get 2.5 rotations a finger pass? that would throw mine off, I am to lazy to go back and correct the work -
Date: Thu, Apr 30 2009 23:58:25
I'm getting dissie...
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Date: Fri, May 1 2009 00:22:36
um guys...
we're talking about how pro he is. not caculating his speed... -
Date: Fri, May 1 2009 00:27:28
fingerpass god
amazing, keep up the good work. -
Date: Fri, May 1 2009 01:09:27
Lol, blur his camera a bit + make it at Bonkura fingerpass video angle = exact Bonkura copy/ bonkura LOL
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Date: Fri, May 1 2009 03:50:13
OMG that was unbeliveble!
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Date: Fri, May 1 2009 04:18:56
I can calculate his fingerpass speed.
91 fp s-1 = godlike
i understand shimo's explaination though.
EDIT: fp s-1 that's fingerpasses per second
Now I would totally love to see that in real life. -
Date: Fri, May 1 2009 18:52:55
Thanks for all the comments, guys! Going back and looking through all of the comments at once is really cool. Ill try to get a 100/min as soon as possible for you guys.
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Date: Sat, May 2 2009 03:43:17
Damn... it's fucking fast
I only can do about 60 per min ...................
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Date: Sun, May 3 2009 16:09:35
I think i started to cry a bit........
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Date: Sun, May 3 2009 16:34:42QUOTE (Poseidon @ May 3 2009, 12:09 PM) <{POST_SNAPBACK}>I think i started to cry a bit........
I did the same thing when I saw Bonkura's for the first time! XD -
Date: Sun, May 3 2009 20:00:20
How many FP/minute was Bonkura able to do?
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Date: Mon, May 4 2009 02:55:21
this would make a nice gif,repeating and repeating, if the hand was steady
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Date: Tue, May 5 2009 11:08:54QUOTE (Freeman @ May 4 2009, 06:00 AM) <{POST_SNAPBACK}>How many FP/minute was Bonkura able to do?
97/1 minute, but that was about a year (maybe a bit more) before he passed away...RIP bonkura
he could probably do more. -
Date: Tue, May 5 2009 12:22:51QUOTE (i.suk.at.everything @ May 5 2009, 06:08 AM) <{POST_SNAPBACK}>97/1 minute, but that was about a year (maybe a bit more) before he passed away...RIP bonkura
he could probably do more.
I'm pretty sure that Bonkura couldn't do 97FP/ 1min -
Date: Wed, May 6 2009 06:59:57QUOTE (Nam Dang @ May 5 2009, 10:22 PM) <{POST_SNAPBACK}>I'm pretty sure that Bonkura couldn't do 97FP/ 1min
11 in a bit under 6 seconds with a normal dr grip in one tribute vid somewhere. and look at his fingerpass tut video as well, and i doubt that's his best.
he can probably do more. *cbf digging up post where i read he could do 97 fp/min in 2006* -
Date: Wed, May 6 2009 19:32:37QUOTE (Awesome @ Apr 30 2009, 10:29 PM) <{POST_SNAPBACK}>14144.13 cm = 14.14413 m not KM so its significantly less, then you take stevieboy's calculation and add it on to this result for the vertical distance so
14.14 + 16.38= 30.52m
v=d/t
30.52/60= 0.51~ m/ sec, for the total speed of one of the ends (assuming all other calculations were correct), Stevies was right however as he said in a vertical sense, so his answer wasn't worried about the rotations.
and how did you get 2.5 rotations a finger pass? that would throw mine off, I am to lazy to go back and correct the work
14144.13 cm = 141.4413 m, as 1 m = 100 cm
^^ -
Date: Sun, May 10 2009 19:13:50
Wow ! You're amazing !