UPSB v3

Off-topic / math help thx

how?

  1. Clyde
    Date: Tue, Oct 27 2009 10:46:35

    _/a-6(square root) + 3(3 is not included in the square root) = _/a+9 (square root)

    I know what you do nxt is you square both sides to cancel the radical

    =

    (_/a-6 +3)(_/a-6 +3) = (_/a+9)^2
    =????????????????(my guess was _/a^2+6_/a-6+9)= a+9

    help thx

    wait I asked a help from my friend and I tried to solve it again

    Clyde Cazenas: _/a-6 + 3 = _/a+9
    Clyde Cazenas: (_/a-6 + 3 = _/a+9)^2
    Clyde Cazenas: = a-6 +6_/a-6 + 9 = a + 9
    Clyde Cazenas: a - 6 + 9 = a+9 - 6_/a-6
    Clyde Cazenas: a+3 = a+3_/a-6
    Clyde Cazenas: = a^2 + 6a + 9 =a^2 + 6a + 9 +a - 6
    Clyde Cazenas: a = 6

    ??? did I do it right


    LAST EDIT:

    Clyde Cazenas: _/a-6 + 3 = _/a+9
    Clyde Cazenas: = a-6 + 6_/a-6 + 9 = a+ 9
    Clyde Cazenas: 6_/a-6 = a+ 9 -a+6-9
    Clyde Cazenas: 6_/a-6 = 6
    Clyde Cazenas: (6_/a-6 = 6)^2
    Clyde Cazenas: 36(a-6)=36
    Clyde Cazenas: 36a-216 = 36
    Clyde Cazenas: 36a = 252
    Clyde Cazenas: a =7

    thx to this other smart friend of mine who helped me...he said I got a mistake in combining unlike terms so...

    mods delete this

  2. Zombo
    Date: Thu, Oct 29 2009 06:15:23

    well this is really easy to check

    just plug in the value you found for a back into the original equation if its right then you're right.

  3. Jaybles
    Date: Thu, Oct 29 2009 15:39:15

    For reference:

    www.rogercortesi.com/eqn/index.php

  4. pakspinner
    Date: Thu, Oct 29 2009 21:47:57

    what math are u taking.

  5. Erirornal Kraione
    Date: Thu, Oct 29 2009 23:23:50

    What is this I don't even.

    No idea what you're asking there.

  6. Clyde
    Date: Thu, Oct 29 2009 23:36:06

    _/ = radical sign idk how to type the radical sign sry

  7. Awesome
    Date: Fri, Oct 30 2009 02:54:29

    QUOTE (Clyde @ Oct 29 2009, 07:36 PM) <{POST_SNAPBACK}>
    _/ = radical sign idk how to type the radical sign sry

    you can just put them to the exponent of 1/2 for square root 1/3 for cubed roots and so on.

    if you have a graphing calculator you can check you answer by graphing the 2 functions and look at their point of intersection, or as zombo said sub the number back in.

  8. Clyde
    Date: Fri, Oct 30 2009 02:56:55

    QUOTE (Awesome @ Oct 30 2009, 10:54 AM) <{POST_SNAPBACK}>
    you can just put them to the exponent of 1/2 for square root 1/3 for cubed roots and so on.

    if you have a graphing calculator you can check you answer by graphing the 2 functions and look at their point of intersection, or as zombo said sub the number back in.

    i already solved it lol...sure to pass math quarterly exam hehehe