UPSB v3
Off-topic / math help thx
how?
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Date: Tue, Oct 27 2009 10:46:35
_/a-6(square root) + 3(3 is not included in the square root) = _/a+9 (square root)
I know what you do nxt is you square both sides to cancel the radical
=
(_/a-6 +3)(_/a-6 +3) = (_/a+9)^2
=????????????????(my guess was _/a^2+6_/a-6+9)= a+9
help thx
wait I asked a help from my friend and I tried to solve it again
Clyde Cazenas: _/a-6 + 3 = _/a+9
Clyde Cazenas: (_/a-6 + 3 = _/a+9)^2
Clyde Cazenas: = a-6 +6_/a-6 + 9 = a + 9
Clyde Cazenas: a - 6 + 9 = a+9 - 6_/a-6
Clyde Cazenas: a+3 = a+3_/a-6
Clyde Cazenas: = a^2 + 6a + 9 =a^2 + 6a + 9 +a - 6
Clyde Cazenas: a = 6
??? did I do it right
LAST EDIT:
Clyde Cazenas: _/a-6 + 3 = _/a+9
Clyde Cazenas: = a-6 + 6_/a-6 + 9 = a+ 9
Clyde Cazenas: 6_/a-6 = a+ 9 -a+6-9
Clyde Cazenas: 6_/a-6 = 6
Clyde Cazenas: (6_/a-6 = 6)^2
Clyde Cazenas: 36(a-6)=36
Clyde Cazenas: 36a-216 = 36
Clyde Cazenas: 36a = 252
Clyde Cazenas: a =7
thx to this other smart friend of mine who helped me...he said I got a mistake in combining unlike terms so...
mods delete this -
Date: Thu, Oct 29 2009 06:15:23
well this is really easy to check
just plug in the value you found for a back into the original equation if its right then you're right. -
Date: Thu, Oct 29 2009 15:39:15
For reference:
www.rogercortesi.com/eqn/index.php -
Date: Thu, Oct 29 2009 21:47:57
what math are u taking.
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Date: Thu, Oct 29 2009 23:23:50
What is this I don't even.
No idea what you're asking there. -
Date: Thu, Oct 29 2009 23:36:06
_/ = radical sign idk how to type the radical sign sry
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Date: Fri, Oct 30 2009 02:54:29QUOTE (Clyde @ Oct 29 2009, 07:36 PM) <{POST_SNAPBACK}>_/ = radical sign idk how to type the radical sign sry
you can just put them to the exponent of 1/2 for square root 1/3 for cubed roots and so on.
if you have a graphing calculator you can check you answer by graphing the 2 functions and look at their point of intersection, or as zombo said sub the number back in. -
Date: Fri, Oct 30 2009 02:56:55QUOTE (Awesome @ Oct 30 2009, 10:54 AM) <{POST_SNAPBACK}>you can just put them to the exponent of 1/2 for square root 1/3 for cubed roots and so on.
if you have a graphing calculator you can check you answer by graphing the 2 functions and look at their point of intersection, or as zombo said sub the number back in.
i already solved it lol...sure to pass math quarterly exam hehehe